I'm trying to figure out how to wire this loop. I have used the internal SPDT switches built into the Tortoise switch motor to handle the polarity of the dead-end that goes up to the right but I cannot, for the life of me, figure out how to power the frog properly depending on which direction the turnout is switched. [edit: I've used one SPDT on each tortoise to power the frogs on all other turnouts but there's only two SPDT switches on a tortoise so I can't reverse the polarity for the loop *and* power the frog on this particular one.]
Illustration:
Currently this is a DC layout. I've labeled the polarity for discussion on the image above. The most northerly rail is + in this case. The continuous interior bend eventually goes over the red rails and then eventually comes back around and is connected to the red rails. Effectively it is a basic figure 8 shape but bent into an L. There is a turnout that is out of frame to the left that brings locos in off the main line into the blue area.
As I said I already have the polarity of the blue track to the right of the blue turnout reversing depending on the direction of the turnout (when it's thrown the polarity changes properly to match the connecting rails).
The frog however does not match and I cannot connect the frog to both of course since that'd be a short. I tried connecting two diodes up how I thought they should work but that did not work. It shorted. Maybe I am misunderstanding what diodes do or maybe I overheated them while desoldering them to get them off something else and one or both of them are damaged. I don't have anymore though to play with right now.
In the schematic below the blue turnout is switched to go straight through (not thrown). The north spur rail polarity is the same as the north rail on the main line.
In the schematic below the opposite is true. The turnout is thrown (RH) up to the most northerly turnout onto the main line. The north spur rail polarity is the opposite of the north mainline rail.
This all works fine, as I said. But the big question... How do I power the frog on this bottom blue turnout?
When the turnout is thrown the frog should be powered from the north bus. Can I accomplish this with some creative use of diodes? or something?
Thanks for reading!
Illustration:
Currently this is a DC layout. I've labeled the polarity for discussion on the image above. The most northerly rail is + in this case. The continuous interior bend eventually goes over the red rails and then eventually comes back around and is connected to the red rails. Effectively it is a basic figure 8 shape but bent into an L. There is a turnout that is out of frame to the left that brings locos in off the main line into the blue area.
As I said I already have the polarity of the blue track to the right of the blue turnout reversing depending on the direction of the turnout (when it's thrown the polarity changes properly to match the connecting rails).
The frog however does not match and I cannot connect the frog to both of course since that'd be a short. I tried connecting two diodes up how I thought they should work but that did not work. It shorted. Maybe I am misunderstanding what diodes do or maybe I overheated them while desoldering them to get them off something else and one or both of them are damaged. I don't have anymore though to play with right now.
In the schematic below the blue turnout is switched to go straight through (not thrown). The north spur rail polarity is the same as the north rail on the main line.
In the schematic below the opposite is true. The turnout is thrown (RH) up to the most northerly turnout onto the main line. The north spur rail polarity is the opposite of the north mainline rail.
This all works fine, as I said. But the big question... How do I power the frog on this bottom blue turnout?
When the turnout is thrown the frog should be powered from the north bus. Can I accomplish this with some creative use of diodes? or something?
Thanks for reading!
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